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Saturday, 31 October

JEE Main 2024 · PhysicsMultiple choiceSingle correctEasyApplication

JEE Main 9 April 2024, Shift 2, Physics Q42

Question 42 of 90 in this shift, Physics question 12 of 30, Section A.

Five charges +q+q, +5q+5q, −2q-2q, +3q+3q and −4q-4q are situated as shown in the figure. The electric flux due to this configuration through the surface SS is :

The figure, in words

Closed irregular surface S. Inside S: charges +5q, +q and -2q. Outside S: +3q (right of the surface) and -4q (left of the surface).
  1. (1)4qϵ0\frac{4q}{\epsilon_0}Official answer
  2. (2)5qϵ0\frac{5q}{\epsilon_0}
  3. (3)3qϵ0\frac{3q}{\epsilon_0}
  4. (4)qϵ0\frac{q}{\epsilon_0}

Official answer

Option 1

NTA final key.

Same topic in other shifts

All Gauss's Law questions
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  3. 8 Apr 2025, Shift 2 · Q36An infinitely long wire has uniform linear charge density λ=2\lambda = 2 nC/m. The net flux through a Gaussian cube of side length…MediumSingle correct
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  5. 4 Apr 2024, Shift 2 · Q41A charge qq is placed at the center of one of the surface of a cube. The flux linked with the cube is:MediumSingle correct
  6. 6 Apr 2024, Shift 1 · Q38σ\sigma is the uniform surface charge density of a thin spherical shell of radius RR. The electric field at any point on the surface of…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.