JEE Main 2024 (9 Apr, Shift 1) Physics Q60: Nuclei

Question

A star has $100\%$ helium composition. It starts to convert three ${}^4\mathrm{He}$ into one ${}^{12}\mathrm{C}$ via triple alpha process as ${}^4\mathrm{He}+{}^4\mathrm{He}+{}^4\mathrm{He}	o{}^{12}\mathrm{C}+Q$. The mass of the star is $2.0	imes10^{32}$ kg and it generates energy at the rate of $5.808	imes10^{30}$ W. The rate of converting these ${}^4\mathrm{He}$ to ${}^{12}\mathrm{C}$ is $n	imes10^{42}\ \mathrm{s^{-1}}$, where n is ________.
[ Take, mass of ${}^4\mathrm{He}=4.0026$ u, mass of ${}^{12}\mathrm{C}=12$ u]

Accepted Answer

5

JEE Main 9 April 2024, Shift 1, Physics Q60

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