Learn

Saturday, 31 October

JEE Main 2024 · PhysicsNumerical answerNumerical valueMediumCalculation

JEE Main 8 April 2024, Shift 2, Physics Q54

Question 54 of 90 in this shift, Physics question 24 of 30, Section B.

An object of mass 0.2 kg executes simple harmonic motion along x axis with frequency of (25π)\left(\frac{25}{\pi}\right) Hz. At the position x=0.04x = 0.04 m the object has kinetic energy 0.5 J and potential energy 0.4 J. The amplitude of oscillation is __________ cm.

Official answer

6

NTA final key.

Chapter
Oscillations
Topic
Energy in SHM
Idea tested
Kinetic Energy in SHM

Same idea in other shifts

Asked 2× in all
  1. 13 Apr 2023, Shift 1 · Q57At a given point of time the value of displacement of a simple harmonic oscillator is given as y=Acos⁡(30∘)y = A\cos(30^\circ). If amplitude is 40…MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.