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Saturday, 31 October

JEE Main 2024 · PhysicsMultiple choiceSingle correctEasyConceptual

JEE Main 8 April 2024, Shift 2, Physics Q47

Question 47 of 90 in this shift, Physics question 17 of 30, Section A.

If MoM_o is the mass of isotope 512B{}^{12}_{5}\mathrm{B}, MPM_P and MnM_n are the masses of proton and neutron, then nuclear binding energy of isotope is :
  1. (1)(Mo−5Mp)C2(M_o - 5M_p)C^2
  2. (2)(Mo−12Mn)C2(M_o - 12M_n)C^2
  3. (3)(5Mp+7Mn−Mo)C2(5M_p + 7M_n - M_o)C^2Official answer
  4. (4)(Mo−5Mp−7Mn)C2(M_o - 5M_p - 7M_n)C^2

Official answer

Option 3

NTA final key.

Chapter
Nuclei
Topic
Nuclear Binding Energy
Idea tested
Total Binding Energy

Same idea in other shifts

Asked 3× in all
  1. 9 Apr 2024, Shift 1 · Q47The energy equivalent of 11 g of substance is :EasySingle correct
  2. 25 Jul 2021, Shift 2 · Q28From the given data, the amount of energy required to break the nucleus of aluminium 1327Al^{27}_{13}\mathrm{Al} is __________…EasyNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.