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Saturday, 31 October

JEE Main 2024 · PhysicsMultiple choiceSingle correctEasyConceptual

JEE Main 8 April 2024, Shift 2, Physics Q31

Question 31 of 90 in this shift, Physics question 1 of 30, Section A.

If ϵ0\epsilon_0 is the permittivity of free space and E is the electric field, then ϵ0E2\epsilon_0 E^2 has the dimensions :
  1. (1)[M0L−2TA][M^0 L^{-2} T A]
  2. (2)[M−1L−3T4A2][M^{-1} L^{-3} T^4 A^2]
  3. (3)[ML2T−2][M L^2 T^{-2}]
  4. (4)[ML−1T−2][M L^{-1} T^{-2}]Official answer

Official answer

Option 4

NTA final key.

Chapter
Units and Measurements
Topic
Coulomb's Law
Idea tested
Dimensional Analysis of Permittivity

Same idea in other shifts

Asked 3× in all
  1. 2 Apr 2025, Shift 2 · Q35If μ0\mu_0 and ϵ0\epsilon_0 are the permeability and permittivity of free space, respectively, then the dimension of…EasySingle correct
  2. 8 Apr 2023, Shift 1 · Q46Dimension of 1μ0ϵ0\frac{1}{\mu_0 \epsilon_0} should be equal toEasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.