JEE Main 2024 · PhysicsMultiple choiceSingle correctMediumMulti-step

JEE Main 6 April 2024, Shift 2, Physics Q42

Question 42 of 90 in this shift, Physics question 12 of 30, Section A.

Two identical conducting spheres

P

and

S

with charge

Q

on each, repel each other with a force 16 N. A third identical uncharged conducting sphere

R

is successively brought in contact with the two spheres. The new force of repulsion between

P

and

S

is :

(1)6 NOfficial answer
(2)12 N
(3)4 N
(4)1 N

Official answer

Option 1

NTA final key.

Chapter: Electric Charges and Fields
Topic: Coulomb's Law
Idea tested: Charge Redistribution via Conduction

Same idea in other shifts

Asked 3× in all

29 Jul 2022, Shift 2 · Q31Two identical metallic spheres A and B when placed at certain distance in air repel each other with a force of F. Another identical…MediumSingle correct
25 Feb 2021, Shift 2 · Q27Two identical conducting spheres with negligible volume have 2.1 nC and $-$ 0.1 nC charges, respectively. They are brought into contact and…EasyNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.