If the area of the region $\left\{(x,y):\frac{a}{x^2}\le y\le\frac{1}{x},\ 1\le x\le 2,\ 0<a<1\right\}$ is $(\log_e 2)-\frac{1}{7}$ then the value of $7a-3$ is equal to :

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JEE Main 6 April 2024, Shift 2, Maths Q11

Question 11 of 90 in this shift, Maths question 11 of 30, Section A.

If the area of the region

\left\{(x,y):\frac{a}{x^2}\le y\le\frac{1}{x},\ 1\le x\le 2,\ 0<a<1\right\}

(\log_e 2)-\frac{1}{7}

then the value of

7a-3

is equal to :

Official answer

Option 1

NTA final key.