JEE Main 2024 · ChemistryNumerical answerNumerical valueEasyCalculation

JEE Main 5 April 2024, Shift 2, Chemistry Q90

Question 90 of 90 in this shift, Chemistry question 30 of 30, Section B.

X g of ethanamine was subjected to reaction with

\mathrm{NaNO_2/HCl}

followed by hydrolysis to liberate

\mathrm{N_2}

and HCl. The HCl generated was completely neutralised by 0.2 moles of NaOH. X is ________ g.

Official answer

NTA final key.

Chapter: Amines
Topic: Amines
Idea tested: Reaction of Primary Aliphatic Amines with HNO2

Same idea in other shifts

Asked 3× in all

4 Apr 2024, Shift 1 · Q90X g of ethylamine is subjected to reaction with $\mathrm{NaNO_2}$ /HCl followed by water; evolved dinitrogen gas which occupied 2.24 L…EasyNumerical value
28 Jun 2022, Shift 1 · Q77A primary aliphatic amine on reaction with nitrous acid in cold (273 K) and there after raising temperature of reaction mixture to room…EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.