JEE Main 2024 · MathsNumerical answerNumerical valueMediumMulti-step

JEE Main 5 April 2024, Shift 2, Maths Q26

Question 26 of 90 in this shift, Maths question 26 of 30, Section B.

Let

y = y(x)

be the solution of the differential equation

\frac{dy}{dx} + \frac{2x}{(1+x^2)^2}\,y = x e^{\frac{1}{(1+x^2)}}

;

y(0) = 0

. Then the area enclosed by the curve

f(x) = y(x)\,e^{-\frac{1}{(1+x^2)}}

and the line

y-x=4

is ________.

Official answer

NTA final key.

Chapter: Differential Equations
Topic: Linear Differential Equations
Idea tested: General Solution Formula

Same idea in other shifts

Asked 3× in all

7 Apr 2025, Shift 2 · Q19Let $y=y(x)$ be the solution of the differential equation $(x^2+1)y'-2xy=(x^4+2x^2+1)\cos x$ , $y(0)=1$ . Then $\int_{-3}^{3}y(x)\,dx$ is :MediumSingle correct
25 Feb 2021, Shift 1 · Q69If a curve passes through the origin and the slope of the tangent to it at any point $(x, y)$ is $\frac{x^2 - 4x + y + 8}{x - 2}$ , then…HardSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.