JEE Main 2024 · ChemistryNumerical answerNumerical valueMediumCalculation

JEE Main 5 April 2024, Shift 1, Chemistry Q84

Question 84 of 90 in this shift, Chemistry question 24 of 30, Section B.

An artificial cell is made by encapsulating 0.2 M glucose solution within a semipermeable membrane. The osmotic pressure developed when the artificial cell is placed within a 0.05 M solution of NaCl at 300 K is ________

\times 10^{-1}

bar. (nearest integer). [Given : R = 0.083 L bar mol

^{-1}

^{-1}

] Assume complete dissociation of NaCl

Official answer

NTA final key.

Chapter: Solutions
Topic: Colligative Properties
Idea tested: Osmotic Pressure

Same idea in other shifts

Asked 7× in all

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.