JEE Main 2024 · PhysicsNumerical answerNumerical valueMediumCalculation

JEE Main 5 April 2024, Shift 1, Physics Q59

Question 59 of 90 in this shift, Physics question 29 of 30, Section B.

If three helium nuclei combine to form a carbon nucleus then the energy released in this reaction is ________

\times10^{-2}

MeV. (Given 1 u = 931 MeV/

c^2

, atomic mass of helium = 4.002603u)

Official answer

727

NTA final key.

Chapter: Nuclei
Topic: Nuclear Binding Energy
Idea tested: Mass Defect Calculation

Same idea in other shifts

Asked 5× in all

5 Apr 2026, Shift 2 · Q44Assuming the experimental mass of ${}^{12}_{6}\mathrm{C}$ as 12 u, the mass defect of ${}^{12}_{6}\mathrm{C}$ atom is ________…EasySingle correct
8 Apr 2024, Shift 1 · Q46Binding energy of a certain nucleus is $18\times10^8$ J. How much is the difference between total mass of all the nucleons and nuclear…EasySingle correct
31 Jan 2024, Shift 1 · Q60The mass defect in a particular reaction is 0.4g. The amount of energy liberated is $n\times10^7$ kWh, where $n=$ _______. (speed of light…EasyNumerical value
3 Aug 2021, Shift 2 · Q12If $A$ , $Z$ and $M$ represents the number of nucleons, protons and mass of the nucleus respectively, then mass defect $\Delta M$ is…EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.