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Saturday, 31 October

JEE Main 2024 · PhysicsMultiple choiceDiagram basedEasyCalculation

JEE Main 5 April 2024, Shift 1, Physics Q42

Question 42 of 90 in this shift, Physics question 12 of 30, Section A.

In the given figure R1=10ΩR_1 = 10\Omega, R2=8ΩR_2 = 8\Omega, R3=4ΩR_3 = 4\Omega and R4=8ΩR_4 = 8\Omega. Battery is ideal with emf 12V. Equivalent resistant of the circuit and current supplied by battery are respectively :

The figure, in words

Circuit: 12 V ideal battery (+ on top) in series with R1 on the top wire; to the right, R2 and R3 are in two vertical branches between the top and bottom wires, and R4 is drawn as a diagonal resistor connecting the bottom end of R2 (bottom-left node) to the top end of R3 (top-right node).
  1. (1)10.5 Ω10.5\ \Omega and 1.141.14 A
  2. (2)12 Ω12\ \Omega and 11.411.4 A
  3. (3)12 Ω12\ \Omega and 11 AOfficial answer
  4. (4)10.5 Ω10.5\ \Omega and 11 A

Official answer

Option 3

NTA final key.

Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.