JEE Main 2024 · ChemistryNumerical answerNumerical valueEasyConceptual

JEE Main 4 April 2024, Shift 2, Chemistry Q81

Question 81 of 90 in this shift, Chemistry question 21 of 30, Section B.

The maximum number of orbitals which can be identified with n = 4 and

m_l

= 0 is ________.

Official answer

NTA final key.

Chapter: Structure of Atom
Topic: Quantum Numbers
Idea tested: Magnetic Quantum Number

Same idea in other shifts

Asked 7× in all

5 Apr 2024, Shift 2 · Q81In an atom, total number of electrons having quantum numbers $n=4$ , $|m_l|=1$ and $m_s=-\frac{1}{2}$ is ________.MediumNumerical value
28 Jul 2022, Shift 1 · Q61Identify the incorrect statement from the following.MediumSingle correct
31 Aug 2021, Shift 1 · Q52Ge ( $\mathrm{Z}=32$ ) in its ground state electronic configuration has $x$ completely filled orbitals with $\mathrm{m}_l=0$ . The value of…MediumNumerical value
31 Aug 2021, Shift 2 · Q53The value of magnetic quantum number of the outermost electron of $\mathrm{Zn^+}$ ion is __________. (Integer answer)EasyNumerical value
16 Mar 2021, Shift 2 · Q53The number of orbitals with $n=5$ , $m_l=+2$ is ________. (Round off to the Nearest Integer).EasyNumerical value
2 Sep 2020, Shift 2 · Q30The number of subshells associated with $n=4$ and $m=-2$ quantum numbers is :MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.