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JEE Main 2024 · PhysicsMultiple choiceSingle correctEasyConceptual

JEE Main 4 April 2024, Shift 2, Physics Q50

Question 50 of 90 in this shift, Physics question 20 of 30, Section A.

In simple harmonic motion, the total mechanical energy of given system is

E

. If mass of oscillating particle

P

is doubled then the new energy of the system for same amplitude is:

The figure, in words

A mass

m

(labelled

P

) hangs from a vertical spring of constant

k

attached to a fixed ceiling.

(1) $E\sqrt{2}$
(2) $E/\sqrt{2}$
(3) $2E$
(4) $E$ Official answer

Official answer

Option 4

NTA final key.

Chapter: Oscillations
Topic: Energy in SHM
Idea tested: Total Mechanical Energy

Same idea in other shifts

Asked 2× in all

6 Apr 2026, Shift 2 · Q36A spring stretches by 2 mm when it is loaded with a mass of 200 g. From equilibrium position the mass is further pulled down by 2 mm and…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.