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Saturday, 31 October

JEE Main 2024 · MathsNumerical answerNumerical valueHardMulti-step

JEE Main 4 April 2024, Shift 2, Maths Q27

Question 27 of 90 in this shift, Maths question 27 of 30, Section B.

Let y=y(x)y=y(x) be the solution of the differential equation (x+y+2)2dx=dy(x+y+2)^2dx=dy, y(0)=−2y(0)=-2. Let the maximum and minimum values of the function y=y(x)y=y(x) in [0,π3]\left[0,\frac{\pi}{3}\right] be α\alpha and β\beta, respectively. If (3α+π)2+β2=γ+δ3(3\alpha+\pi)^2+\beta^2=\gamma+\delta\sqrt3, γ,δ∈Z\gamma,\delta\in\mathbb{Z}, then γ+δ\gamma+\delta equals __________

Official answer

31

NTA final key.