If the mean of the following probability distribution of a radam variable X: X: 0, 2, 4, 6, 8 P(X): $a$, $2a$, $a+b$, $2b$, $3b$ is $\frac{46}{9}$, then the variance of the distribution is

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JEE Main 4 April 2024, Shift 2, Maths Q19

Question 19 of 90 in this shift, Maths question 19 of 30, Section A.

If the mean of the following probability distribution of a radam variable X: X: 0, 2, 4, 6, 8 P(X):

a

2a

a+b

2b

3b

\frac{46}{9}

, then the variance of the distribution is

Official answer

Option 2

NTA final key.