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Saturday, 31 October

JEE Main 2024 · PhysicsNumerical answerNumerical valueMediumCalculation

JEE Main 4 April 2024, Shift 1, Physics Q53

Question 53 of 90 in this shift, Physics question 23 of 30, Section B.

A soap bubble is blown to a diameter of 7 cm. 36960 erg of work is done in blowing it further. If surface tension of soap solution is 40 dyne/cm then the new radius is ________ cm Take (π=227)\left(\pi = \frac{22}{7}\right).

Official answer

7

NTA final key.

Chapter
Mechanical Properties of Fluids
Topic
Surface Tension
Idea tested
Surface Energy and Work

Same idea in other shifts

Asked 2× in all
  1. 11 Apr 2023, Shift 2 · Q52The surface tension of soap solution is 3.5×10−2 Nm−13.5\times10^{-2}\ \mathrm{Nm^{-1}}. The amount of work done required to increase the radius of…MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.