JEE Main 2024 · PhysicsMultiple choiceDiagram basedEasyData or graph
JEE Main 4 April 2024, Shift 1, Physics Q46
Question 46 of 90 in this shift, Physics question 16 of 30, Section A.
Which figure shows the correct variation of applied potential difference (V) with photoelectric current (I) at two different intensities of light () of same wavelengths :
The figure, in words
Four i-V graphs as options (axes i vertical, V horizontal, -V0 marked on the negative V-axis), curves labelled I1 and I2.- (1)[figure: graph of i vs V; curve I1 starts at -V0 on the V-axis, curve I2 starts at a point to the right of -V0 (smaller magnitude of stopping potential) and rises more steeply to a higher saturation, crossing I1]
- (2)[figure: graph of i vs V; I1 and I2 both start at the same point -V0 on the V-axis, I2 lies above I1 and saturates higher]Official answer
- (3)[figure: graph of i vs V; I1 starts at -V0 and saturates lower; I2 starts from the origin (V = 0) and rises steeply, crossing I1 and saturating higher]
- (4)[figure: graph of i vs V; I2 starts at -V0, I1 starts at a point slightly to the right of -V0, I2 lies above I1 and both saturate]
Official answer
Option 2
NTA final key.
- Topic
- Photoelectric Effect
- Idea tested
- Intensity vs Frequency Effects