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JEE Main 2024 · MathsMultiple choiceSingle correctEasyMulti-step

JEE Main 4 April 2024, Shift 1, Maths Q3

Question 3 of 90 in this shift, Maths question 3 of 30, Section A.

If 2 and 6 are the roots of the equation

ax^2+bx+1=0

, then the quadratic equation, whose roots are

\frac{1}{2a+b}

and

\frac{1}{6a+b}

, is :

(1) $x^2+8x+12=0$ Official answer
(2) $4x^2+14x+12=0$
(3) $2x^2+11x+12=0$
(4) $x^2+10x+16=0$

Official answer

Option 1

NTA final key.

Chapter: Complex Numbers and Quadratic Equations
Topic: Quadratic Roots
Idea tested: Transformation of Roots

Same idea in other shifts

Asked 2× in all

28 Jul 2022, Shift 2 · Q62Let $\alpha,\beta$ be the roots of the equation $x^2-\sqrt{2}\,x+\sqrt{6}=0$ and $\frac{1}{\alpha^2}+1,\ \frac{1}{\beta^2}+1$ be the roots…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.