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Saturday, 31 October

JEE Main 2023 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 13 April 2023, Shift 2, Physics Q32

Question 32 of 90 in this shift, Physics question 2 of 30, Section A.

The distance travelled by an object in time t is given by s=(2.5)t2s=(2.5)t^2. The instantaneous speed of the object at t=5t=5 s will be:
  1. (1)5 ms−15\ \mathrm{ms^{-1}}
  2. (2)12.5 ms−112.5\ \mathrm{ms^{-1}}
  3. (3)25 ms−125\ \mathrm{ms^{-1}}Official answer
  4. (4)62.5 ms−162.5\ \mathrm{ms^{-1}}

Official answer

Option 3

NTA final key.