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Saturday, 31 October

JEE Main 2023 · MathsMultiple choiceSingle correctMediumApplication

JEE Main 13 April 2023, Shift 2, Maths Q15

Question 15 of 90 in this shift, Maths question 15 of 30, Section A.

The line, that is coplanar to the line x+3−3=y−11=z−55\frac{x+3}{-3}=\frac{y-1}{1}=\frac{z-5}{5}, is
  1. (1)x−1−1=y−22=z−55\frac{x-1}{-1}=\frac{y-2}{2}=\frac{z-5}{5}
  2. (2)x+1−1=y−22=z−55\frac{x+1}{-1}=\frac{y-2}{2}=\frac{z-5}{5}Official answer
  3. (3)x+1−1=y−22=z−54\frac{x+1}{-1}=\frac{y-2}{2}=\frac{z-5}{4}
  4. (4)x+11=y−22=z−55\frac{x+1}{1}=\frac{y-2}{2}=\frac{z-5}{5}

Official answer

Option 2

NTA final key.