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Saturday, 31 October

JEE Main 2023 · ChemistryMultiple choiceDiagram basedEasyRecall

JEE Main 12 April 2023, Shift 1, Chemistry Q68

Question 68 of 90 in this shift, Chemistry question 8 of 30, Section A.

In the given reaction cycle CaCl2+Na2CO3⟶X‾+Y‾\mathrm{CaCl_2 + Na_2CO_3 \longrightarrow \underline{X} + \underline{Y}} with an arrow from the underlined X back up to CaCl2\mathrm{CaCl_2} via a path labelled Z X, Y and Z respectively are

The figure, in words

Reaction cycle: CaCl2 + Na2CO3 -> X + Y (X, Y underlined blanks); a return arrow from X back to CaCl2 labelled Z. Options list X, Y, Z columns.
  1. (1)X: CaO\mathrm{CaO}, Y: NaCl+CO2\mathrm{NaCl + CO_2}, Z: NaCl\mathrm{NaCl}
  2. (2)X: CaO\mathrm{CaO}, Y: NaCl+CO2\mathrm{NaCl + CO_2}, Z: KCl\mathrm{KCl}
  3. (3)X: CaCO3\mathrm{CaCO_3}, Y: NaCl\mathrm{NaCl}, Z: HCl\mathrm{HCl}Official answer
  4. (4)X: CaCO3\mathrm{CaCO_3}, Y: NaCl\mathrm{NaCl}, Z: KCl\mathrm{KCl}

Official answer

Option 3

NTA final key.

Chapter
The s-Block Elements
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.