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Saturday, 31 October

JEE Main 2023 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 11 April 2023, Shift 2, Physics Q38

Question 38 of 90 in this shift, Physics question 8 of 30, Section A. NTA dropped this question from the final key; it is left out of every count on this site.

When vector A⃗=2i^+3j^+2k^\vec{A} = 2\hat{i}+3\hat{j}+2\hat{k} is subtracted from vector B⃗\vec{B}, it gives a vector equal to 2j^2\hat{j}. Then the magnitude of vector B⃗\vec{B} will be :
  1. (1)33
  2. (2)5\sqrt{5}
  3. (3)13\sqrt{13}
  4. (4)6\sqrt{6}

Official answer

Dropped by NTA (marks given to all)

NTA final key: NTA final key: DROP (question dropped).

Topic
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Idea tested
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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.