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Saturday, 31 October

JEE Main 2023 · PhysicsMultiple choiceDiagram basedMediumData or graph

JEE Main 10 April 2023, Shift 2, Physics Q45

Question 45 of 90 in this shift, Physics question 15 of 30, Section A.

The variation of stopping potential (V0V_0) as a function of the frequency (ν\nu) of the incident light for a metal is shown in figure. The work function of the surface is

The figure, in words

Graph of stopping potential V0 (volt, vertical axis marked 1, 2, 3) versus frequency nu (x10^14 Hz, horizontal axis marked 1 to 10): a straight line starting on the frequency axis at nu = 5 and rising to about 2.5 V at nu = 10.
  1. (1)1.361.36 eV
  2. (2)2.982.98 eV
  3. (3)2.072.07 eVOfficial answer
  4. (4)18.618.6 eV

Official answer

Option 3

NTA final key.

Chapter
Dual Nature of Radiation and Matter
Topic
Photoelectric Effect
Idea tested
Stopping Potential vs Frequency Graph

Same idea in other shifts

Asked 4× in all
  1. 6 Apr 2023, Shift 2 · Q44The work functions of Aluminium and Gold are 4.1 eV and and 5.1 eV respectively. The ratio of the slope of the stopping potential versus…EasySingle correct
  2. 4 Sep 2020, Shift 1 · Q20Given figure shows few data points in a photo electric effect experiment for a certain metal. The minimum energy for ejection of electron…MediumDiagram basedHas a figure
  3. 4 Sep 2020, Shift 2 · Q17In a photoelectric effect experiment, the graph of stopping potential V versus reciprocal of wavelength obtained is shown in the figure.…EasyDiagram basedHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.