In the figure, $\theta_1 + \theta_2 = \frac{\pi}{2}$ and $\sqrt{3}\,(BE) = 4(AB)$. If the area of $\Delta CAB$ is $2\sqrt{3} - 3$ unit$^2$, when $\frac{\theta_2}{\theta_1}$ is the largest, then the perimeter (in unit) of $\Delta CED$ is equal to ___________.

JEE Main 2023 · MathsNumerical answerNumerical valueHardDiagram reading

JEE Main 10 April 2023, Shift 2, Maths Q30

Question 30 of 90 in this shift, Maths question 30 of 30, Section B.

In the figure,

\theta_1 + \theta_2 = \frac{\pi}{2}

and

\sqrt{3}\,(BE) = 4(AB)

. If the area of

\Delta CAB

2\sqrt{3} - 3

unit

^2

, when

\frac{\theta_2}{\theta_1}

is the largest, then the perimeter (in unit) of

\Delta CED

is equal to ___________.

The figure, in words

Right-angled figure: A bottom-left and B bottom-right with AB horizontal; C directly above A, D directly above B (CD horizontal); E directly above D (BE vertical through D). Segments CB and CE are drawn. Right angles marked at A, D and B (between BA and BD/BE). theta_1 is the angle at B between BA and BC; theta_2 is the angle at C between CD and CE.

Official answer

NTA final key.

Chapter: Trigonometric Functions
Topic: Properties of Triangles
Idea tested: Sine Rule Application

JEE Main 10 April 2023, Shift 2, Maths Q30

Same idea in other shifts