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Saturday, 31 October

JEE Main 2023 · MathsMultiple choiceSingle correctHardMulti-step

JEE Main 10 April 2023, Shift 2, Maths Q10

Question 10 of 90 in this shift, Maths question 10 of 30, Section A.

For α,β,γ,δ∈N\alpha, \beta, \gamma, \delta \in \mathbb{N}, if ∫((xe)2x+(ex)2x)log⁡ex dx=1α(xe)βx−1γ(ex)δx+C\int \left(\left(\frac{x}{e}\right)^{2x} + \left(\frac{e}{x}\right)^{2x}\right) \log_e x \, dx = \frac{1}{\alpha}\left(\frac{x}{e}\right)^{\beta x} - \frac{1}{\gamma}\left(\frac{e}{x}\right)^{\delta x} + C , where e=∑n=0∞1n!e = \sum_{n=0}^{\infty} \frac{1}{n!} and CC is constant of integration, then α+2β+3γ−4δ\alpha + 2\beta + 3\gamma - 4\delta is equal to
  1. (1)−8-8
  2. (2)−4-4
  3. (3)11
  4. (4)44Official answer

Official answer

Option 4

NTA final key.

Chapter
Integrals