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Saturday, 31 October

JEE Main 2023 · PhysicsNumerical answerNumerical valueEasyCalculation

JEE Main 10 April 2023, Shift 1, Physics Q59

Question 59 of 90 in this shift, Physics question 29 of 30, Section B.

The current required to be passed through a solenoid of 15 cm length and 60 turns in order to demagnetise a bar magnet of magnetic intensity 2.4×103 Am−12.4\times10^{3}\,Am^{-1} is ____________ A.

Official answer

6

NTA final key.

Chapter
Magnetism and Matter
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.