Learn

Saturday, 31 October

JEE Main 2023 · PhysicsMultiple choiceOtherMediumConceptual

JEE Main 8 April 2023, Shift 1, Physics Q43

Question 43 of 90 in this shift, Physics question 13 of 30, Section A.

For a nucleus ZAX{}^{A}_{Z}\mathrm{X} having mass number A and atomic number Z A. The surface energy per nucleon (bs)=−a1A2/3(\mathrm{b_s}) = -a_1 A^{2/3}. B. The Coulomb contribution to the binding energy bc=−a2Z(Z−1)A4/3\mathrm{b_c} = -a_2\frac{Z(Z-1)}{A^{4/3}} C. The volume energy bv=a3A\mathrm{b_v} = a_3 A D. Decrease in the binding energy is proportional to surface area. E. While estimating the surface energy, it is assumed that each nucleon interacts with 12 nucleons. (a1a_1, a2a_2 and a3a_3 are constants) Choose the most appropriate answer from the options given below:
  1. (1)A, B, C, D only
  2. (2)B, C only
  3. (3)C, D onlyOfficial answer
  4. (4)B, C, E only

Official answer

Option 3

NTA final key.

Chapter
Nuclei