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Saturday, 31 October

JEE Main 2023 · PhysicsNumerical answerNumerical valueMediumCalculation

JEE Main 6 April 2023, Shift 2, Physics Q57

Question 57 of 90 in this shift, Physics question 27 of 30, Section B.

A proton with a kinetic energy of 2.0 eV moves into a region of uniform magnetic field of magnitude π2×10−3\frac{\pi}{2}\times10^{-3} T. The angle between the direction of magnetic field and velocity of proton is 60∘60^\circ. The pitch of the helical path taken by the proton is ________ cm. (Take, mass of proton = 1.6×10−271.6\times10^{-27} kg and Charge on proton = 1.6×10−191.6\times10^{-19} C).

Official answer

40

NTA final key.