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Saturday, 31 October

JEE Main 2023 · PhysicsNumerical answerNumerical valueMediumCalculation

JEE Main 6 April 2023, Shift 2, Physics Q55

Question 55 of 90 in this shift, Physics question 25 of 30, Section B.

A beam of light consisting of two wavelengths 7000 Å and 5500 Å is used to obtain interference pattern in Young's double slit experiment. The distance between the slits is 2.5 mm and the distance between the plane of slits and the screen is 150 cm. The least distance from the central fringe, where the bright fringes due to both the wavelengths coincide, is n×10−5n\times10^{-5}m. The value of nn is __________.

Official answer

462

NTA final key.

Chapter
Wave Optics
Topic
Young's Double Slit
Idea tested
Coinciding Maxima of Two Wavelengths

Same idea in other shifts

Asked 2× in all
  1. 4 Apr 2024, Shift 1 · Q59Two wavelengths λ1\lambda_1 and λ2\lambda_2 are used in Young's double slit experiment. λ1=450\lambda_1 = 450 nm and λ2=650\lambda_2 = 650 nm. The…MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.