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Saturday, 31 October

JEE Main 2022 · ChemistryMultiple choiceDiagram basedEasyApplication

JEE Main 30 June 2022, Shift 1, Chemistry Q74

Question 74 of 90 in this shift, Chemistry question 14 of 30, Section A.

Consider the given chemical reaction [structure: a six-membered saturated carbon ring bearing a C(=O)OH group (carbonyl O drawn above the carbon, OH to its right)] →(ii) H2O(i) Red P, Cl2\xrightarrow[\text{(ii) } \mathrm{H_2O}]{\text{(i) Red P, } \mathrm{Cl_2}} P (Major Product) Identify the product P.

The figure, in words

Reactant: cyclic six-membered carbon ring with a C(=O)OH substituent; reagents (i) Red P, Cl2 (ii) H2O over arrow to P, Major Product. Options are drawn ring structures.
  1. (1)[figure: six-membered saturated carbon ring with Cl and C(=O)OH both attached to the same ring carbon]Official answer
  2. (2)[figure: six-membered saturated carbon ring with a C(=O)Cl group attached]
  3. (3)[figure: six-membered saturated carbon ring with C(=O)OH on one ring carbon and Cl on a ring carbon separated from it by one ring carbon]
  4. (4)[figure: six-membered saturated carbon ring with C(=O)OH on one ring carbon and Cl on the opposite ring carbon]

Official answer

Option 1

NTA final key.