JEE Main 2022 (30 Jun, Shift 1) Physics Q46: LCR Resonance

Question

In series RLC resonator, if the self inductance and capacitance become double, the new resonant frequency ($f_2$) and new quality factor ($\mathrm{Q_2}$) will be :
($f_1$=original resonant frequency, $\mathrm{Q_1}$=original quality factor)

Accepted Answer

Option 1: $f_2=\frac{f_1}{2}$ and $\mathrm{Q_2}=\mathrm{Q_1}$

Answer

$f_2=\frac{f_1}{2}$ and $\mathrm{Q_2}=\mathrm{Q_1}$

Answer

$f_2=f_1$ and $\mathrm{Q_2}=\frac{\mathrm{Q_1}}{2}$

Answer

$f_2=2f_1$ and $\mathrm{Q_2}=\mathrm{Q_1}$

Answer

$f_2=f_1$ and $\mathrm{Q_2}=2\mathrm{Q_1}$

JEE Main 30 June 2022, Shift 1, Physics Q46

Same idea in other shifts