JEE Main 2022 · PhysicsMultiple choiceSingle correctMediumCalculation

JEE Main 30 June 2022, Shift 1, Physics Q43

Question 43 of 90 in this shift, Physics question 13 of 30, Section A.

A cyclotron is working at a frequency of 10 MHz. If the radius of its dees is 60 cm. The maximum kinetic energy of accelerated proton will be : (Take : e=

1.6\times10^{-19}

\mathrm{m_p}

1.67\times10^{-27}

kg)

(1)7.4 MeVOfficial answer
(2)14.86 MeV
(3)7.4 GeV
(4)704 GeV

Official answer

Option 1

NTA final key.

Chapter: Moving Charges and Magnetism
Topic: Lorentz Force
Idea tested: Cyclotron Frequency and Energy

Same idea in other shifts

Asked 4× in all

4 Apr 2025, Shift 2 · Q49A particle of charge 1.6 $\mu$ C and mass 16 $\mu$ g is present in a strong magnetic field of 6.28 T. The particle is then fired…EasyNumerical value
27 Jul 2022, Shift 2 · Q43A cyclotron is used to accelerate protons. If the operating magnetic field is 1.0 T and the radius of the cyclotron 'dees' is 60 cm, the…EasySingle correct
26 Aug 2021, Shift 2 · Q25If the maximum value of accelerating potential provided by a radio frequency oscillator is 12 kV. The number of revolution made by a…MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.