JEE Main 2022 · ChemistryMultiple choiceSingle correctMediumCalculation

JEE Main 29 June 2022, Shift 2, Chemistry Q64

Question 64 of 90 in this shift, Chemistry question 4 of 30, Section A.

4.0 moles of argon and 5.0 moles of

\mathrm{PCl_5}

are introduced into an evacuated flask of 100 litre capacity at 610 K. The system is allowed to equilibrate. At equilibrium, the total pressure of mixture was found to be 6.0 atm. The

\mathrm{K_p}

for the reaction is [Given: R = 0.082 L atm

\mathrm{K^{-1}}

\mathrm{mol^{-1}}

]

(1)2.25Official answer
(2)6.24
(3)12.13
(4)15.24

Official answer

Option 1

NTA final key.

Chapter: Equilibrium
Topic: Chemical Equilibrium
Idea tested: Kp Expression via Partial Pressures

Same idea in other shifts

Asked 4× in all

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24 Jun 2022, Shift 2 · Q83PCl $_5$ dissociates as PCl $_5$ (g) $\rightleftharpoons$ PCl $_3$ (g)+Cl $_2$ (g) 5 moles of PCl $_5$ are placed in a 200 litre vessel which…HardNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.