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Saturday, 31 October

JEE Main 2022 · PhysicsNumerical answerNumerical valueEasyCalculation

JEE Main 29 June 2022, Shift 2, Physics Q51

Question 51 of 90 in this shift, Physics question 21 of 30, Section B.

The Vernier constant of Vernier callipers is 0.1 mm and it has zero error of (−0.05) cm. While measuring diameter of a sphere, the main scale reading is 1.7 cm and coinciding vernier division is 5. The corrected diameter will be ________ × 10−210^{-2} cm.

Official answer

180

NTA final key.

Chapter
Units and Measurements
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.