JEE Main 2022 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 29 June 2022, Shift 2, Physics Q42

Question 42 of 90 in this shift, Physics question 12 of 30, Section A.

The motion of a simple pendulum executing S.H.M. is represented by the following equation.

y = A\sin(\pi t + \phi)

, where time is measured in second. The length of pendulum is

(1)97.23 cm
(2)25.3 cm
(3)99.4 cmOfficial answer
(4)406.1 cm

Official answer

Option 3

NTA final key.

Chapter: Oscillations
Topic: Pendulums
Idea tested: Simple Pendulum Period

Same idea in other shifts

Asked 4× in all

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22 Jul 2021, Shift 2 · Q20 $\mathrm{T_0}$ is the time period of a simple pendulum at a place. If the length of the pendulum is reduced to $\frac{1}{16}$ times of its…EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.