JEE Main 2022 · PhysicsMultiple choiceSingle correctMediumApplication

JEE Main 29 June 2022, Shift 1, Physics Q36

Question 36 of 90 in this shift, Physics question 6 of 30, Section A.

A wire of length L is hanging from a fixed support. The length changes to

L_1

and

L_2

when masses 1 kg and 2 kg are suspended respectively from its free end. Then the value of L is equal to :

(1) $\sqrt{L_1L_2}$
(2) $\frac{L_1 + L_2}{2}$
(3) $2L_1 - L_2$ Official answer
(4) $3L_1 - 2L_2$

Official answer

Option 3

NTA final key (2022 Session 1).

Chapter: Mechanical Properties of Solids
Topic: Elasticity
Idea tested: Finding Natural Length from Two Tensions

Same idea in other shifts

Asked 3× in all

2 Apr 2025, Shift 2 · Q48The length of a light string is 1.4 m when the tension on it is 5 N. If the tension increases to 7 N, the length of the string is 1.56 m.…EasyNumerical value
26 Feb 2021, Shift 2 · Q15The length of metallic wire is $l_1$ when tension in it is $T_1$ . It is $l_2$ when the tension is $T_2$ . The original length of the wire…EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.