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Saturday, 31 October

JEE Main 2022 · MathsNumerical answerNumerical valueMediumCalculation

JEE Main 29 June 2022, Shift 1, Maths Q26

Question 26 of 90 in this shift, Maths question 26 of 30, Section B.

50tan⁡(3tan⁡−1(12)+2cos⁡−1(15))+42tan⁡(12tan⁡−1(22))50\tan\left(3\tan^{-1}\left(\frac{1}{2}\right) + 2\cos^{-1}\left(\frac{1}{\sqrt{5}}\right)\right) + 4\sqrt{2}\tan\left(\frac{1}{2}\tan^{-1}(2\sqrt{2})\right) is equal to ____________.

Official answer

29

NTA final key (2022 Session 1).