JEE Main 2022 · ChemistryNumerical answerNumerical valueHardCalculation

JEE Main 28 June 2022, Shift 2, Chemistry Q84

Question 84 of 90 in this shift, Chemistry question 24 of 30, Section B.

For the given reactions

\mathrm{Sn^{2+} + 2e^- \rightarrow Sn}

\mathrm{Sn^{4+} + 4e^- \rightarrow Sn}

the electrode potentials are ;

\mathrm{E^o_{Sn^{2+}/Sn}} = -0.140

V and

\mathrm{E^o_{Sn^{4+}/Sn}} = 0.010

V. The magnitude of standard electrode potential for

\mathrm{Sn^{4+}/Sn^{2+}}

i.e.

\mathrm{E^o_{Sn^{4+}/Sn^{2+}}}

is __________

\times10^{-2}

V. (Nearest integer)

Official answer

NTA final key.

Same idea in other shifts