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Saturday, 31 October

JEE Main 2022 · MathsMultiple choiceSingle correctHardMulti-step

JEE Main 28 June 2022, Shift 2, Maths Q8

Question 8 of 90 in this shift, Maths question 8 of 30, Section A.

Let f:R→Rf : \mathbf{R} \to \mathbf{R} be a continuous function satisfying f(x)+f(x+k)=nf(x)+f(x+k)=n, for all x∈Rx \in \mathbf{R} where k>0k>0 and n is a positive integer. If I1=∫04nkf(x)dxI_1=\int_0^{4nk} f(x)dx and I2=∫−k3kf(x)dxI_2=\int_{-k}^{3k} f(x)dx, then :
  1. (1)I1+2I2=4nkI_1+2I_2=4nk
  2. (2)I1+2I2=2nkI_1+2I_2=2nk
  3. (3)I1+nI2=4n2kI_1+nI_2=4n^2kOfficial answer
  4. (4)I1+nI2=6n2kI_1+nI_2=6n^2k

Official answer

Option 3

NTA final key.

Chapter
Integrals