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Saturday, 31 October

JEE Main 2022 · ChemistryMultiple choiceDiagram basedMediumApplication

JEE Main 28 June 2022, Shift 2, Chemistry Q74

Question 74 of 90 in this shift, Chemistry question 14 of 30, Section A.

The major product (P) of the given reaction is (where, Me is −CH3-\mathrm{CH_3}) [reaction: reactant →H+\xrightarrow{\mathrm{H^+}} P (Major Product)]

The figure, in words

Reactant: cyclohexane ring with Me on the upper-left ring carbon, OH on the upper-right ring carbon, and two Me groups (one drawn to the right, one drawn straight down) on the lower-right ring carbon adjacent to the OH-bearing carbon. Arrow labelled H+ gives P, Major Product.
  1. (1)[figure: cyclohexene ring; Me on the ring carbon at upper left; C=C double bond between the top ring carbon and the upper-right ring carbon; gem-dimethyl (two Me) on the lower-right ring carbon]
  2. (2)[figure: cyclohexene ring; Me on the ring carbon at upper left; Me on the upper-right ring carbon; C=C double bond between the lower-right ring carbon (bearing a Me) and the bottom ring carbon]
  3. (3)[figure: cyclohexene ring; Me on the ring carbon at upper left; C=C double bond between the upper-right ring carbon (bearing a Me) and the lower-right ring carbon (bearing a Me)]Official answer
  4. (4)[figure: cyclohexane ring; Me on the ring carbon at upper left; Me on the upper-right ring carbon; exocyclic C=CH2 double bond on the lower-right ring carbon]

Official answer

Option 3

NTA final key.

Same topic in other shifts

All Alkenes and Alkynes questions
  1. 4 Apr 2026, Shift 1 · Q64An alkene (X) on ozonolysis followed by reduction gives following products. H−CHO\mathrm{H-CHO} (2 moles), OHC−CO−CHO\mathrm{OHC-CO-CHO}…HardDiagram basedHas a figure
  2. 4 Apr 2026, Shift 2 · Q64Compound (X) is subjected to the sequence of reactions as shown above. Molar mass of the major product (Y) formed is ________…MediumDiagram basedHas a figure
  3. 5 Apr 2026, Shift 1 · Q64"P" is a hydrocarbon of molecular formula:- C8H14\mathrm{C_8H_{14}}. On ozonolysis, "P" forms "Q". "Q" on treatment with alkali under reflux…HardDiagram basedHas a figure
  4. 6 Apr 2026, Shift 1 · Q66Given below are two statements: Statement I: 3-phenylpropene reacts with HBr and gives secondary alkyl bromide having a chiral carbon atom…MediumTwo statements
  5. 6 Apr 2026, Shift 2 · Q65An optically active alkyl bromide C4H9Br\mathrm{C_4H_9Br}, reacts with ethanolic KOH to form major compound [A] which reacts with bromine to…MediumSingle correct
  6. 2 Apr 2025, Shift 1 · Q66An optically active alkyl halide C4H9Br\mathrm{C_4H_9Br} [A] reacts with hot KOH dissolved in ethanol and forms alkene [B] as major product…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.