JEE Main 2022 · ChemistryMultiple choiceDiagram basedMediumApplication
JEE Main 28 June 2022, Shift 2, Chemistry Q74
Question 74 of 90 in this shift, Chemistry question 14 of 30, Section A.
The major product (P) of the given reaction is
(where, Me is )
[reaction: reactant P (Major Product)]
The figure, in words
Reactant: cyclohexane ring with Me on the upper-left ring carbon, OH on the upper-right ring carbon, and two Me groups (one drawn to the right, one drawn straight down) on the lower-right ring carbon adjacent to the OH-bearing carbon. Arrow labelled H+ gives P, Major Product.- (1)[figure: cyclohexene ring; Me on the ring carbon at upper left; C=C double bond between the top ring carbon and the upper-right ring carbon; gem-dimethyl (two Me) on the lower-right ring carbon]
- (2)[figure: cyclohexene ring; Me on the ring carbon at upper left; Me on the upper-right ring carbon; C=C double bond between the lower-right ring carbon (bearing a Me) and the bottom ring carbon]
- (3)[figure: cyclohexene ring; Me on the ring carbon at upper left; C=C double bond between the upper-right ring carbon (bearing a Me) and the lower-right ring carbon (bearing a Me)]Official answer
- (4)[figure: cyclohexane ring; Me on the ring carbon at upper left; Me on the upper-right ring carbon; exocyclic C=CH2 double bond on the lower-right ring carbon]
Official answer
Option 3
NTA final key.
- Chapter
- Alcohols, Phenols and Ethers
- Topic
- Alkenes and Alkynes
- Idea tested
- Acid-Catalyzed Dehydration of Alcohols