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Saturday, 31 October

JEE Main 2022 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 28 June 2022, Shift 2, Physics Q50

Question 50 of 90 in this shift, Physics question 20 of 30, Section A.

Amplitude modulated wave is represented by VAM=10[1+0.4cos⁡(2π×104t)]cos⁡(2π×107t)V_{AM}=10\left[1+0.4\cos(2\pi\times10^{4}t)\right]\cos(2\pi\times10^{7}t). The total bandwidth of the amplitude modulated wave is :
  1. (1)10 kHz
  2. (2)20 MHz
  3. (3)20 kHzOfficial answer
  4. (4)10 MHz

Official answer

Option 3

NTA final key.

Chapter
Communication Systems
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.