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Saturday, 31 October

JEE Main 2022 · MathsMultiple choiceSingle correctMediumCalculation

JEE Main 28 June 2022, Shift 2, Maths Q4

Question 4 of 90 in this shift, Maths question 4 of 30, Section A.

The term independent of xx in the expansion of (1−x2+3x3)(52x3−15x2)11(1-x^2+3x^3)\left(\frac{5}{2}x^3-\frac{1}{5x^2}\right)^{11}, x≠0x \neq 0 is :
  1. (1)740\frac{7}{40}
  2. (2)33200\frac{33}{200}Official answer
  3. (3)39200\frac{39}{200}
  4. (4)1150\frac{11}{50}

Official answer

Option 2

NTA final key.