JEE Main 2022 · ChemistryMultiple choiceDiagram basedMediumConceptual

JEE Main 28 June 2022, Shift 1, Chemistry Q74

Question 74 of 90 in this shift, Chemistry question 14 of 30, Section A.

The correct structure of product ‘A’ formed in the following reaction,

\mathrm{PhCHO + Ph \cdot CHO} \xrightarrow[\text{in } \mathrm{D_2O}]{\mathrm{NaOD}} A + \mathrm{Ph-C(=O)-O^-}

(Ph is -

\mathrm{C_6H_5}

) is

The figure, in words

Stem reaction: PhCHO + Ph·CHO with NaOD in D2O gives A + Ph-C(=O)-O(-) (the C=O drawn above the carbon). Each option is a single carbon drawn with Ph at lower left, OD or OH going up, and two further substituents at right (H or D) as described.

(1)[figure: one carbon bonded to Ph, OD, H and H]Official answer
(2)[figure: one carbon bonded to Ph, OH, H and H]
(3)[figure: one carbon bonded to Ph, OD, D and H]
(4)[figure: one carbon bonded to Ph, OD, D and D]

Official answer

Option 1

NTA final key.

Chapter: Aldehydes, Ketones and Carboxylic Acids
Topic: Aldol and Cannizzaro
Idea tested: Cannizzaro Reaction

JEE Main 28 June 2022, Shift 1, Chemistry Q74

Same idea in other shifts