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JEE Main 2022 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 28 June 2022, Shift 1, Physics Q43

Question 43 of 90 in this shift, Physics question 13 of 30, Section A.

The aperture of the objective is 24.4 cm. The resolving power of this telescope, if a light of wavelength 2440

\mathrm{\AA}

is used to see the object will be :

(1) $8.1\times10^{6}$
(2) $10.0\times10^{7}$
(3) $8.2\times10^{5}$ Official answer
(4) $1.0\times10^{-8}$

Official answer

Option 3

NTA final key.

Chapter: Ray Optics and Optical Instruments
Topic: Single Slit Diffraction
Idea tested: Resolving Power of a Telescope

Same idea in other shifts

Asked 2× in all

8 Apr 2026, Shift 2 · Q47Some distant star is to be observed by some telescope of diameter of objective lens $a$ , at an angular resolution of $3.0 \times 10^{-7}$ …EasyNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.