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Saturday, 31 October

JEE Main 2022 · MathsMultiple choiceSingle correctMediumCalculation

JEE Main 27 June 2022, Shift 2, Maths Q5

Question 5 of 90 in this shift, Maths question 5 of 30, Section A.

Let S=2+67+1272+2073+3074+… ..S=2+\frac{6}{7}+\frac{12}{7^2}+\frac{20}{7^3}+\frac{30}{7^4}+\dots.. Then 4S4S is equal to
  1. (1)(73)2\left(\frac{7}{3}\right)^2
  2. (2)7332\frac{7^3}{3^2}
  3. (3)(73)3\left(\frac{7}{3}\right)^3Official answer
  4. (4)7233\frac{7^2}{3^3}

Official answer

Option 3

NTA final key.