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Saturday, 31 October

JEE Main 2022 · ChemistryMultiple choiceDiagram basedHardMulti-step

JEE Main 27 June 2022, Shift 1, Chemistry Q79

Question 79 of 90 in this shift, Chemistry question 19 of 30, Section A.

L-isomer of a compound ‘A’ (C4H8O4\mathrm{C_4H_8O_4}) gives a positive test with [Ag(NH3)2]+\mathrm{[Ag(NH_3)_2]^+}. Treatment of ‘A’ with acetic anhydride yields triacetate derivative. Compound ‘A’ produces an optically active compound (B) and an optically inactive compound (C) on treatment with bromine water and HNO3\mathrm{HNO_3} respectively. Compound (A) is :

The figure, in words

All four options are Fischer projections drawn with CHO at the top, CH2OH at the bottom and two stereocentres between, differing only in which side (left/right) the OH and H are drawn on each of the two middle carbons.
  1. (1)[figure: Fischer projection, CHO at top and CH2OH\mathrm{CH_2OH} at bottom; the two middle carbons carry HO on the left and H on the right (upper), HO on the left and H on the right (lower)]Official answer
  2. (2)[figure: Fischer projection, CHO at top and CH2OH\mathrm{CH_2OH} at bottom; upper middle carbon has H on the left and OH on the right, lower middle carbon has HO on the left and H on the right]
  3. (3)[figure: Fischer projection, CHO at top and CH2OH\mathrm{CH_2OH} at bottom; upper middle carbon has H on the left and OH on the right, lower middle carbon has H on the left and OH on the right]
  4. (4)[figure: Fischer projection, CHO at top and CH2OH\mathrm{CH_2OH} at bottom; upper middle carbon has HO on the left and H on the right, lower middle carbon has H on the left and OH on the right]

Official answer

Option 1

NTA final key.