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Saturday, 31 October

JEE Main 2022 · PhysicsMultiple choiceSingle correctMediumApplication

JEE Main 27 June 2022, Shift 1, Physics Q31

Question 31 of 90 in this shift, Physics question 1 of 30, Section A.

A projectile is launched at an angle ‘α\alpha’ with the horizontal with a velocity 20 ms−120\ \mathrm{ms^{-1}}. After 10 s10\ \mathrm{s}, its inclination with horizontal is ‘β\beta’. The value of tan⁡β\tan\beta will be : (g=10 ms−2g=10\ \mathrm{ms^{-2}}).
  1. (1)tan⁡α+5sec⁡α\tan\alpha+5\sec\alpha
  2. (2)tan⁡α−5sec⁡α\tan\alpha-5\sec\alphaOfficial answer
  3. (3)2tan⁡α−5sec⁡α2\tan\alpha-5\sec\alpha
  4. (4)2tan⁡α+5sec⁡α2\tan\alpha+5\sec\alpha

Official answer

Option 2

NTA final key.