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Saturday, 31 October

JEE Main 2022 · ChemistryNumerical answerNumerical valueEasyCalculation

JEE Main 26 June 2022, Shift 1, Chemistry Q83

Question 83 of 90 in this shift, Chemistry question 23 of 30, Section B.

50 mL of 0.1 M CH3COOH\mathrm{CH_3COOH} is being titrated against 0.1 M NaOH. When 25 mL of NaOH has been added, the pH of the solution will be __________ ×10−2\times10^{-2} . (Nearest integer) (Given : pKa\mathrm{pK_a} (CH3COOH\mathrm{CH_3COOH})=4.76) log 2=0.30 log 3=0.48 log 5=0.69 log 7=0.84 log 11=1.04

Official answer

476

NTA final key.

Same idea in other shifts

Asked 2× in all
  1. 2 Apr 2026, Shift 2 · Q56At 25°C, 20.0 mL of 0.2 M weak monoprotic acid HX is titrated against 0.2 M NaOH. The pH of the solution (a) at the start of the titration…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.