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Saturday, 31 October

JEE Main 2022 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 26 June 2022, Shift 1, Physics Q38

Question 38 of 90 in this shift, Physics question 8 of 30, Section A.

Time period of a simple pendulum in a stationary lift is 'T'. If the lift accelerates with g6\frac{g}{6} vertically upwards then the time period will be : (Where g=acceleration due to gravity)
  1. (1)65 T\sqrt{\frac{6}{5}}\,T
  2. (2)56 T\sqrt{\frac{5}{6}}\,T
  3. (3)67 T\sqrt{\frac{6}{7}}\,TOfficial answer
  4. (4)76 T\sqrt{\frac{7}{6}}\,T

Official answer

Option 3

NTA final key.

Chapter
Oscillations
Topic
Pendulums
Idea tested
Effective Gravity Effects

Same idea in other shifts

Asked 2× in all
  1. 30 Jul 2022, Shift 2 · Q9An oscillating simple pendulum of time period To\mathrm{T_o} is placed in a lift which is accelerating upwards with 2.5 m/s22.5\ \mathrm{m/s^2}…EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.